2x^2-10x-44=28

Solution for 2x^2-10x-44=28 equation:

2x^2-10x-44=28

We move all terms to the left:

2x^2-10x-44-(28)=0

We add all the numbers together, and all the variables

2x^2-10x-72=0

a = 2; b = -10; c = -72;
Δ = b2-4ac
Δ = -102-4·2·(-72)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-26}{2*2}=\frac{-16}{4}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+26}{2*2}=\frac{36}{4}
=9
$